Question

if the length of the diameter with end points (2, 4) and (- 2, a) is 5 units , find the equation of the circle .​

Answer 1

Answer:

I think you want to ask find 'a'

if I am right

then

(2,4) take it as pont A. where x1=2 ,y1=4

(-2,a) as point B. where x2=-2 ,y2=a

and distance=5unit

and we know the distance formula

that is

$distance = \sqrt{ {(x2 - x1)}^{2} + (y2 - y1)} {}^{2}$

5=√[{(-2)-2}² +{a-4}²]

5=√[{-4}² +{a²+4²-2×a×4]

by squaring both side

25=16+{a²+16-8a}

25-16=a²+16-8a

a²-8a+16-9=0

a²-8a+7=0

a²-7a-a+7=0

a(a-7)-1(a-7)=0

(a-7)(a-1)=0

if a-7=0

a=7

a-1=0

a=1

so we can take 7 or 1 as answer

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Answer 2

Step-by-step explanation:

what is the equation for this qsn