Question

If the length of the fence of a parallelogram shaped field is 96 cm and the adjacent sides of the field are in the ratio 5:7, find the dimensions of the field.​

Answer 1

It is given that Length of fence of a parallelogram shaped field is 96 cm.

Length of fence means perimeter.

Perimeter = 96 cm

Ratio of adjacent sides = 5:7

Let the sides be $l$ and $b$.

As per question statement:

$l:b = 5:7\\\Rightarrow \dfrac{l}{b} = \dfrac{5}{7}$

$Let\ \dfrac{l}{b}=\dfrac{5x}{7x}\\\Rightarrow l = 5x\ and \\b = 7x$

We know that perimeter of a parallelogram = $2 \times (l+b)$

$2 \times (l+b) = 96$

Putting the values of $l$ and $b$:

$2 \times (5x+7x) = 96\\\Rightarrow 12x = 48\\\Rightarrow x = 4$

Putting value of $x$ in $l$ and $b$:

$l = 5 \times 4 = 20 cm\\b = 7 \times 4 = 28 cm$

So, the dimensions are 20 cm and 28 cm.

Answer 2

Step-by-step explanation:

Given If the length of the fence of a parallelogram shaped field is 96 cm and the adjacent sides of the field are in the ratio 5:7,  find the dimensions of the field.​

• Given In a parallelogram shaped field the length of the fence is 96 cm.
• So perimeter = 96 cm
• Also adjacent sides of the field are in the ratio 5:7
• So we have 5m and 7m
• So l : b = 5m : 7m
• Or l / b = 5m/7m
• So l = 7m and b = 5m
• Now perimeter of a parallelogram = 2(l + b) = 96
•                                                               2(7m + 5m) = 96
•                                                                   12 m = 48
•                                                                 Or m = 4
• So we get l = 7 x 4 = 28 cm
•     And  m = 5 x 4 = 20 cm

Reference link will be

https://brainly.in/question/18405775