Question

If the length of the filament of a heater is redu6 by 10% the power of heater will

Answer 1

Answer:

4 will be the power of heater

Answer 2

Answer:

we know that P=V^2/R

=V^2/ρl/A

P'=1/(l-10/100l)

P'/P=l/(l-l/10)=10/9

P'-P/P*100=10/9*100

=11%

SO it increases by 11%

Hence, the power of the heater will increase by about 11%.