Math, asked by vasu101, 1 year ago

if the length of the ladder placed against a wall is twice the distance between the foot of the ladder and the wall find the angle made by the ladder with the horizontal

Answers

Answered by wifilethbridge
79

Answer:

The angle made by the ladder with the horizontal is 60°

Step-by-step explanation:

Refer the attached figure

Let the distance between the foot of the ladder and the wall i.e. BC = x

Now we are given that the length of the ladder placed against a wall is twice the distance between the foot of the ladder and the wall

So, Length of Ladder = AC = 2x

Now we are supposed to find the angle made by the ladder with the horizontal i.e. ∠ACB

In ΔABC

Using trigonometric ratio

Cos\theta = \frac{Base}{Hypotenuse}

Cos\theta = \frac{x}{2x}

Cos\theta = \frac{1}{2}

\theta = Cos^{-1}\frac{1}{2}

\theta = Cos^{-1}\frac{1}{2}

\theta =60^{\circ}

Thus the angle made by the ladder with the horizontal is 60°

Attachments:
Answered by karthickeshthilak
0

Answer:

60⁰

Step-by-step explanation:

In ΔABC

Using trigonometric ratio

Cos\theta = \frac{Base}{Hypotenuse}Cosθ=HypotenuseBase

Cos\theta = \frac{x}{2x}Cosθ=2xx

Cos\theta = \frac{1}{2}Cosθ=21

\theta = Cos^{-1}\frac{1}{2}θ=Cos−121

\theta = Cos^{-1}\frac{1}{2}θ=Cos−121

\theta =60^{\circ}θ=60∘

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