if the length of the ladder placed against a wall is twice the distance between the foot of the ladder and the wall find the angle made by the ladder with the horizontal
Answers
Answer:
The angle made by the ladder with the horizontal is 60°
Step-by-step explanation:
Refer the attached figure
Let the distance between the foot of the ladder and the wall i.e. BC = x
Now we are given that the length of the ladder placed against a wall is twice the distance between the foot of the ladder and the wall
So, Length of Ladder = AC = 2x
Now we are supposed to find the angle made by the ladder with the horizontal i.e. ∠ACB
In ΔABC
Using trigonometric ratio
Thus the angle made by the ladder with the horizontal is 60°
Answer:
60⁰
Step-by-step explanation:
In ΔABC
Using trigonometric ratio
Cos\theta = \frac{Base}{Hypotenuse}Cosθ=HypotenuseBase
Cos\theta = \frac{x}{2x}Cosθ=2xx
Cos\theta = \frac{1}{2}Cosθ=21
\theta = Cos^{-1}\frac{1}{2}θ=Cos−121
\theta = Cos^{-1}\frac{1}{2}θ=Cos−121
\theta =60^{\circ}θ=60∘