If the length of the line segment with end points (2, - 6) and (2, y) is 4, find y.
Answers
Answered by
1
distance between two point (x1,y1) & (x2,y2) is {(x2-x1)^2 + (y2-y1)^2}^1/2
4 = {(2-2)^2 + (y+6)^2}^1/2
4 = y + 6
y = -2
4 = {(2-2)^2 + (y+6)^2}^1/2
4 = y + 6
y = -2
Similar questions