Question

If the length of the pendulum is (0.8±0.01)m and time period is (2.5±0.12) s, then calculate the % error in acceleration due to gravity.

Answer 1

Answer:

Given;

( l +/- ∆l ) = ( 0.8 +/- 0.01 ) m

(T +/- ∆T ) = ( 2.5 +/- 0.12 ) s