Question

If the length of the rectangle is 12 cm and the breadth is 10 cm, then find its perimeter ?
​

Answer 1

Given :

• Length of the rectangle = 12 cm
• Breadth of the rectangle = 10 cm

To Find :

• Perimeter of the rectangle.

Conception :

For calculating the perimeter of rectangle, formula is given by,

• $\underline{ \underline{ \boxed{ \tt{ Perimeter_{(Rectangle)} = 2 (l +b) }}}}$

So, by substituting values, we will calculate the perimeter of rectangle.

Calculations :

Formula -

• $\underline{ \underline{ \boxed{ \tt{ Perimeter_{(Rectangle)} = 2 (l +b) }}}}$

Here,

• l = length = 12 cm
• b = breadth = 10 cm

Putting the values in the equation,

→ Perimeter of rectangle = 2 (l + b)

→ Perimeter of rectangle = 2 (12 + 10)

→ Perimeter of rectangle = 2 × 22 cm

→ Perimeter of rectangle = 44 cm.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Extra Information:

Some important formulae related to rectangles :-

• Area of rectangle = length × breadth
• Breadth of rectangle = length ÷ area
• Length of rectangle = Area ÷ breadth
• Perimeter of rectangle = 2 (length + breadth)
• Diagonal of rectangle = √(length)² + (breadth)²

Answer 2

Solution:

❍Let the length of rectangle be 12 cm and breadth of rectangle be 10 cm.

Need to find: The perimeter of rectangle

As we know that,

• Perimeter of rectangle = 2(l + b)

Applying the values,

✎ Perimeter = 2(12 + 10)

✎ Perimeter = 2 × 22

✎ Perimeter = 44 cm

• Therefore,The perimeter of rectangle is 44cm.

_________________________________

More formula's to know:-

✎ Perimeter of rectangle = 2(l + b)

✎ Perimeter of square = 4a

✎ Perimeter of triangle = a + b + c

✎ Perimeter of parallelogram = 2(b + h)

✎ Perimeter of trapezoid = a + b + c + d

✎ Perimeter of hexagon = 6a

_________________________________