If the length of the rectangle is increased by 10% and the breadth is reduced by 10% then the area of the resulting rectangle then the area of original rectangle
Answers
Solution :-
Let us assume that, Length and breadth of original rectangle are 10x cm and 10y cm.
so,
→ Area of rectangle = L * B = 10x * 10y = 100xy cm².
now,
→ New length = 110% of 10x = 11x cm.
→ New breadth = 90% of 10y = 9y cm.
so,
→ Area of resulting rectangle = L * B = 11x * 9y = 99xy cm².
then
→ Area of resulting rectangle decreased by = 100xy - 99xy = xy cm².
therefore,
→ Area of resulting rectangle decreased by = (xy * 100) / 100xy = 1% (Ans.)
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Given : length of rectangle increased by 10% and breadth reduced by 10%
To Find : area resulting rectangle compared to the area of the original rectangle
Solution:
Let say original rectangle = 10L and 10B units
area = 10L * 10B = 100LB sq units
length of rectangle increased by 10% = 10L + (10/100)10L = 11L
breadth of rectangle decreased by 10% = 10B - (10/100)10B =9B
Area of resulting rectangle = 11L * 9B = 99LB sq units
Decrease in area = 100LB - 99LB = LB
% Decrease in area = (LB/100LB) * 100 = 1 %
1 % decrease in area
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