Question

If the length of the rectangle is increased by 10% than the area of the resulting rectangle_____ than the area of the original rectangle.​

Answer 1

Answer:

Let the original length and breadth of the rectangle be L and B respectively.

Then the area = LB

If the length is increased by 10% then the new length L' = (110/100)L = (11/10)L

Let the new breadth be B' so that L'B' = LB

So (11/10)L B' = LB so B' = 10/11 B ie 1/11 less than B = (1/11) 100% less than B

Hence the original breadth should be reduced by 9 1/11% so that that the area remains the same.

Answer 2

Step-by-step explanation:

Given:-

Length and breadth of a rectangle

To find:-

If the length of the rectangle is increased by 10% than the area of the resulting rectangle --- than the area of the original rectangle.?

Solution:-

Let the length of the rectangle be l units

Let the breadth of the rectangle be b units

Area of the rectangle = lb sq.units

Area of the original rectangle = lb sq.units

If the length is increased by 10% then

The length of the new rectangle =

l+10% of l

=> l + (10/100)× l

=> l +(1/10)×l

=> l +(l/10)

=> (10 l+l ) /10

=> 11 l /10 units

Area of the new rectangle =

(11 l / 10)×b sq.units

=> (11/10) lb sq.units

Area of the new rectangle = (11/10) lb sq.units

Area of the original rectangle = lb sq.units

Increasing in the area

= (11/10)lb -lb

=> (11/10-1)lb

=>[(11-10)/10] lb

=> (1/10)lb sq.units

=>0.1 lb units

Answer:-

The area of the new rectangle is (11/10)=1.1 times the area of the original rectangle.

(or)

The area of the new rectangle is 1/10= 0.1 more than the area of the original rectangle.

Used formula:-

• Area of a rectangle = lb sq.units