Math, asked by athmanatchiyar6615, 1 year ago

If the length of the rectangle is increased by 12% and the width by 10%, then what is the percentage change in the area:

Answers

Answered by shahpurb
0

Step-by-step explanation:

Let the Length be 10m

and the Width be 8m

Area= 10x8= 80m^2

increase in length= 10 + (12/100)= 10.12m

increase in width= 8 + (10/100)= 8.1m

New Area= 10.12x 8.1= 81.97m^2

Percentage change= (80/81.97)x 100= 97.59%

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