If the length of the rope is 300m for the kite sail, in order to pull the ship at an angle of 60° and at what vertical height the kite be fixed?
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Given If the length of the rope is 300 m for the kite sail, in order to pull the ship at an angle of 60° and at what vertical height the kite be fixed?
- So length of the rope of the kite is 300 m. The ship is to be pulled at an angle of 60 degree.
- So the triangle formed be ABC where AC is hypotenuse, AB and BC are base and opposite side.
- So theta = 60 degree and hypotenuse (rope length = 300 m)
- So sin theta = perpendicular / hypotenuse
- sin 60 = BC / AC
- √3 / 2 = BC / 300
- 2 BC = √3 x 300 / 2
- BC = 150 x √3
- BC = 259.8 m
- = 260 m
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