Question

If the length of the side of a cube is doubled. How much percent will its total surface area increase?

Answer 1

Let the length of the edge of the cube be 'x' cm
(i) Total surface area = 6x2 cm2

Increased length of the edge = 2x
Total surface area = 6(2x)2 cm2 = 24x2 cm2

If the edge of the cube is doubled surface area of the cube increases by 4 times.

Answer 2

If Side is doubled then ,

T.S.A =
$6 {s}^{2}$
$6 \times 2s \times 2s$
$6 \times {4s}^{2}$
$24 {s}^{2}$
6(2s^2) ÷ 6(s^2)
=24s^2 ÷ 6s^2
= 4 times
= 400%
Hope this helps !