Question

If the length of the side of a cube is thrice of the other cube, then the ratios of their volumes would be

Answer 1

V1/V2=(3x)^3/x^3=27x^3/x^3=27:1 ans

Answer 2

Answer:

The ratios of their volumes would be 27:1.    

Step-by-step explanation:

Given : If the length of the side of a cube is thrice of the other cube.

To find : The ratios of their volumes would be?

Solution :

Let the side of the cube be 'a'.

The volume of the cube is

$V=a^3$

If the length of the side of a cube is thrice of the other cube.

i.e. Side of the new cube is '3a'.

Now, The volume of the new cube is

$V_n=(3a)^3$

$V_n=27a^3$

The ratio of one cube and new other cube is

$R=\frac{V_n}{V}$

$R=\frac{27a^3}{a^3}$

$R=\frac{27}{1}$

$R=27:1$

Therefore, The ratios of their volumes would be 27:1.