Question

if the length of the side of a triangle are in the ratio 3:4:5 and its perimeter is 46cm find its area​

Answer 1

Answer:$89.123145142^{2}$

Step-by-step explanation:

In this question first we need to find the length of the sides of the triangle.

For That: We need to fin the sum of the ratios.

Sum of ratios= 3+4+5=12.

Now we have to calculate the measurement of the sides.

Side a= 3/12 of 46= 11.5cm.

Side b= 4/12 of 46= 15.3cm.

Side c= 5/12 of 46= 19.1cm.

Since in this question we don't get the height of the triangle we'll have to apply the Heron's formula to find the area of the triangle.

Semi-perimeter= 46cm/2= 23cm.

Let us denote the Semi-Perimeter by s.

Heron's Formula=$\sqrt[]{s(s-a)(s-b)(s-c)}$

Solution:

$\sqrt{s(s-a)(s-b)(s-c)}$=$\sqrt{23cm(23cm-11.5cm)(23cm-15.3cm)(23cm-19.1cm)}$

=$\sqrt{23cm*11.5cm*7.7cm*3.9cm}$

=$\sqrt{7942.935cm^{4} }$

=$89.123145142^{2}$

Area of triangle=$89.123145142^{2}$.

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