Question

If the length of the sides forming a right angled triangle are 5x cm and (3x -1)cm and the area of the triangle is 60 cm2, then its hypotenuse is:

Answer 1

Answer:

hypotenuse is 22cm

base is 7 cm

by using pythagoras formula we can solve it

length^2 + base^2 = hypotenuse^2

let length be x

x^2 + 7^2 = 22^2

x^2 + 49 = 484

x^2 = 484-49

x^2 = 435

x = under root 435

Answer 2

Step-by-step explanation:

area of triangle = 1/2×b×h

b= (3x-1)cm

h=(5x)cm

area= 60cm²

1/2(3x-1)(5x)=60

(3x-1)(5x)= 120

15x-5x=120

10x= 120

x= 12cm

b= (3(12)-1)cm

b= 38cm

h= 5(12)cm

h= 60cm

let hypotenuse be y

y²=b²+h². (Pythagoras theorem)

y²= 38²+60²

y²=1444+3600

y=√5044

y=71.02cm