Question

If the length of the simple pendulum is increased by 44% from original length calculate the percentage

Answer 1

T=2π√(l/g)

T=k√l……..(1), where constant k=2π/√g

dT/dl = k/2√l

dT= (k/2√l)×dl……(2)

dividing (2) by (1)

dT/T = 1/2×(dl/l)

(dT/T)×100 = 1/2× (dl/l)×100

=44/2

= 22%(increase)

Answer 2

Answer:22%

Explanation:

44/2=22