Question

If the length of the square is doubled then its area will become hiw many times the original area

Answer 1

Let the length (side) of the square be 'a'
Area = a^2

Now, length is doubled
so,length (side) = 2a
Area = 2a*2a = 4a^2

So final area is 4 times the initial area (4a^a/a^2 = 4 times)
Hope this helps.

Answer 2

Step-by-step explanation:

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