Question

if the length of the square shaped room is (X - 2y) units then find the perimeter and the area of the room in the form of algebraic expression

Answer 1

Solution:

If length of the square shaped room is
$(x - 2y) \: units$
We know that square shape has all sides equal.

Perimeter:
➖➖➖➖

Perimeter of square = 4a

here side of square is (x-2y)

so,

$perimeter = 4(x - 2y) \\ \\ = 4x - 8y \: \: units$

Area:
➖➖➖
Area of square:
${a}^{2} \: {unit}^{2}$

for the given room,area is
$= {(x - 2y)}^{2} \\ \\ = {x}^{2} + 4 {y}^{2} - 4xy \: {unit}^{2}$

Hope it helps you.

Answer 2

Answer:

Step-by-step explanation:

If length of the square shaped room is

We know that square shape has all sides equal.

Perimeter:

➖➖➖➖

Perimeter of square = 4a

here side of square is (x-2y)

so,

Area:

➖➖➖

Area of square:

for the given room,area is

Hope it helps