* If the length of the tangent from (2,5) to the
circle x² + y2-54 +4y +K=0 is ,3
7 then find k.
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Step-by-step explanation:
The radius of the circle, the tangent from (5,4) and the point (5,4) when joined to the center of the circle, (0,−k) forms a right angled triangle.
∴ (length of tangent)2 + (radius)2 = (distance of (5,4) from center of the circle)2
∴ (length of tangent)2+k2=(5−0)2+(4+k)2
∴1+k2=25+k2+8k+16
∴8k+40=0
⇒k=−5
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