If the length of the tangent from (5,4) to the circle x² + y² + 2py=0 is 1
and radius k then A.M. of p, k =
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Answer:
The radius of the circle, the tangent from (5,4) and the point (5,4) when joined to the center of the circle, (0,−k) forms a right angled triangle.
∴ (length of tangent)
2
+ (radius)
2
= (distance of (5,4) from center of the circle)
2
∴ (length of tangent)
2
+k
2
=(5−0)
2
+(4+4)²
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