if the length of the the rectangle is is 6 cm and area is 12 CM then find its perimeter.
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Let i and w be the length and width of the rectangle. We are given:
l=w+6
2(l+w)=60
You have two equations and two unknowns. Solving for l and w gives l = 18 and w = 12. Whence, the area A is given by
A=l⋅w=(18)(12)=216cm2
Let i and w be the length and width of the rectangle. We are given:
l=w+6
2(l+w)=60
You have two equations and two unknowns. Solving for l and w gives l = 18 and w = 12. Whence, the area A is given by
A=l⋅w=(18)(12)=216cm2
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