Question

If the length of whose diagonals are 24cm and 18cm then the area of the rhombus

Answer 1

Step-by-step explanation:

According to question it is given that a rhombus is given with 2 diagnols.

Now, area of rhombus is ( side × side )

Using Pythagoras Theorem

AC^2 = AB^2 + BC^2

AC^2 = 12^2 + 9^2

AC^2 = 144 + 81

AC = 15

Area will be

( 15 × 15 )

225 cm^2

Answer 2

Step-by-step explanation:

Here, we have,

PR=24cm

QS=18 cm,

let the meeting point of PR and QS be O,

In ∆ POS,

PO =12 cm ( diagonal bisect each other)

OS=9cm ( diagonal bisect each other)

<POS=90° ( diagonal perpendiculararly bisect each other)

so,

using Pythagoras,

PS^2=PO^2+OS^2

=(12) ^2+(9) ^2

=144+81

=225

PS=√225

PS=15

So, all four sides of rhombus is 15 cm.

area of rhombus = 1/2 x d1xd2

=1/2x 24x18

=12x 18

=216 cm^2