If the length of wire is halfed and its cross-section area is doubled,then what would be the resistance of wire.(given initially the resistance of wire is R)
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Resistivity of wire=K
Original length=l
New length(l')=l/2
Original area of cross section=A
New area of cross section=A'=2A
Original resistance(R)=Kl/A
New resistance(R')=Kl'/A'=(K×(l/2))/2A
R'=Kl/4A
R'=R/4
So the resistance of the wire becomes one-fourth of it's original value
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