If the length rectangle is 16 cm less than the twice of the breadth and the perimeter is 100 cm then find the dimensions
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Answer:
Let breadth of the rectangle is x.
Then its length will be 2x−16.
According to the problem,
2(length+breadth)=100
2(x+2x−16)=100
or, 6x=132
or, x=22.
Then length is
=2x−16
=44−16=28 cm.
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