If the lengths of the sides of a triangle are 11 cm, 60 cm and 61 cm, then ite arenie
(A) 660 sq.com
880 sq.cm
(c) 145 sq.com
(D) 310 sg.em
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Secondary School Math 5+3 pts
The sides of the triangle are 11 cm 60cm 61 cm find the altitude of the smallest side
Report by Divya1216 23.08.2018
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Dabangg69
Dabangg69 Helping Hand
area = 30×11 = 330
altitude => area = 1/2× 11× altitude
330= 1/2×11× altitude
=>altitude=( 330×2)/11= 30×2 = 60 will be the answer
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Answer:
The altitude of the smallest side is 60 cm.
Step-by-step explanation:
Since, the sides of the triangle are 11 cm , 60 cm, and 61 cm,
⇒ The semi perimeter of the triangle,
s=\frac{11+60+61}{2}=\frac{132}{2}=66\text{ cm}
By the Heron's formula,
The area of the given triangle,
A=\sqrt{s(s-11)(s-60)(s-61)}
=\sqrt{66\times 55\times 6\times 5}=\sqrt{108900}=330\text{ square cm}
Let h be the altitude of the smallest side 11 cm,
Thus, the area of the triangle,
A=\frac{1}{2}\times 11\times h
\implies \frac{1}{2}\times 11\times h = 330
\implies 11 h = 660\implies h = 60\text{ cm}
Thus, the altitude of the smallest side is 60 cm.
Explanation:
use heron's formula for solving this question