Question

If the lengths of the sides of a triangle are 8 cm, 11 cm and 13 cm, then area of the triangle is _______(cm)².
(a) 44
(b) 43
(c) 42.82
(d) 8√30

Answer 1

a = 8 b= 11 c = 13

s = a + b + c/2

=32/2 = 16

area = √s(s-a)(s-b)(s-c)

= √16*(16-8)(16-11)(16-13)

= √16*8*5*3

=8√30 cm²