Math, asked by sharmilaroy094, 1 month ago

If the lengths of the sides of a triangle are in he ratio 3:4:5 and its perimeter is 48 cm, find its area.

Answers

Answered by palpriyanshu9820
0

Answer:

area of triangle is 84.75

Step-by-step explanation:

let the sides be 3x,4x and 5x

perimeter of triangle = 3x+4x+5x

                                 45 = 12x

                                 45/12= x

                                  3.75=x

sides of triangle = 3x=3 3.75= 11.25

                           =4x=4 3.75= 15

                           =5x=5 3.75= 18.75

area of triangle = 84.375

Answered by sampa94765
0

Step-by-step explanation:

Let the sides be x

Therefore, 3x, 4x and 5x

Total perimeter = 48 cm

According to condition,

3x + 4x + 5x = 48

12x = 48

x = 48/12

x = 4

Sides :

3x = 3×4=12cm

4x =4×4=16cm

5x = 5×4=20cm

Semi Permiter = 12+16+20/2 = 48/2= 24cm

Area = √s(s-12) (s-16) (s-20)

= √24(24-12) (24-16) (24-20)

= √24×12×8×4

= √9216

= 96 sq.cm

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