If the lengths of the sides of a triangle are in proportion 3 : 4 : 5 and the perimeter of the triangle is 120 metre, then find the area of the triangle.
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let all angle be x
3x+4x+5x=120
12x=120
x=120/12
x=10
let first angle be 3 ×10= 30
let second Angle be 4x × 10 =40
let third angle be 5 x × 10= 50
then the sum of total angle will be 120
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3x+4x+5x=120
12x=120
x=120/12
x=10
let first angle be 3 ×10= 30
let second Angle be 4x × 10 =40
let third angle be 5 x × 10= 50
then the sum of total angle will be 120
HOPE THIS WILL HELP YOU
MARK ME AS BRAINLIST
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