Question

if the letters of the equation arranged find the number of arrangements in which no two constant occur together ?​

Answer 1

Answer:

Lets arrange the vowels first. There are five of them and you can arrange them in 5! ways.

After you have placed the vowels, you have six spaces left to place the remaining three consonants, four in between the vowels, one before the first and one after the last.

Now, you need to arrange the remaining three consonants in these six spaces. The first consonant will have six choices for its position, the second one will have five and the last one will have four.

So, your answer will be 5!*6*5*4.