If the letters of the word "india" are arranged as in a dictionary,find the rank of the word "india"
Answers
Solution INDIA, total no. of words = 5*4*3*2*1/2*1 = 60 arranged letters A D I I N first letter I, before it there are 2 letters so [60/5]*2 second letter N, before it 3 letters so [12*2/4]*3 (2 is for revision of I) third letter D, before it 1 letter so [6/3]*1 fourth letter I, before it 1 letter so [2/2]*1 so rank = [60/5]*2 + [12*2/4]*3 + [6/3]*1 + [2/2]*1 + 1 = 24+18+2+1+1 = 46 Pls mark as brainliest
Answer:
Concept:
Probability refers to potential. A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1.
Step-by-step explanation:
According to the dictionary, the letters are ADIIN.
Total words beginning with the letter A: 4!/2! = 12
4!/2! = 12 is the total number of words that begin with the letter D.
24 words start with the letter I, which is 4 words overall.
48th letter:
INIDA 47th letter:
INIAD 46th letter:
INDIA 46th rank
(OR)
Another method of solving this:
There are 4!/2! = 12 words that begin with the letter A in total.
4!/2! = 12 words begin with the letter D in total.
Total words beginning with the letter IA: 3! = 6
Total words beginning with letter ID = 3! = 6
Total words beginning with letter II = 3! = 6
There are 2 words that begin with the letter INA in total.
INAID is the 44th word.
INDAI is the 45th word.
India is the 46th word.
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