Math, asked by sharma1569, 2 months ago

if the letters of the word probability are arranged at random in a row what is the probability that the letter BAB must remain together as a unit ( the letter of BAB can arrange themselves but as a whole the letters are together ? pls ans it asap ​

Answers

Answered by mazharalamkhan2002
2

Answer:

Total number of ways in which the letters of the word 'PROBABILITY' can be arranged in a row=

2!2!

11!

Number of ways in which two B's are together =

2!

10!

∴ Required probability = 2!2!

11!

2!

10!

=

11!

10!×2!

=

11

2

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