if the letters of the word probability are arranged at random in a row what is the probability that the letter BAB must remain together as a unit ( the letter of BAB can arrange themselves but as a whole the letters are together ? pls ans it asap
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Answer:
Total number of ways in which the letters of the word 'PROBABILITY' can be arranged in a row=
2!2!
11!
Number of ways in which two B's are together =
2!
10!
∴ Required probability = 2!2!
11!
2!
10!
=
11!
10!×2!
=
11
2
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