Question

If the letters of the word VERMA are arranged in all possible ways and these words are written out as in a dictionary, then the rank of the word VERMA is :
A) 108
B) 117
C) 810
D) 180

Answer 1

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Q)

 

If the letters of the word RACHIT are arranged in all possible ways as listed in dictionary.Then what is the rank of the word RACHIT?

(A)480(B)479(C)481(D)484(A)480(B)479(C)481(D)484



A)

 

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Toolbox:n!=n(n−1)(n−2)(n−3)......(3)(2)(1)n!=n(n−1)(n−2)(n−3)......(3)(2)(1)

If we arrange in alphabetical order we get A C H I

Words start with A=5!

Words start with C=5!

Words start with H=5!

Words start with I=5!

Words start with R is RACHIT

Hence 5!+5!+5!+5!5!+5!+5!+5!

5!=5×4×3×2×1=1205!=5×4×3×2×1=120

120+120+120+120=480120+120+120+120=480

Hence words with R is RACHIT

Thus 480+1=481

Hence (C) is the correct answer.

Answer 2

Hey mate ^_^

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Answer:
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$The\: number \:of \:words \:begin\: with:$

A is $4!$

E is $4!$

M is $4!$  

R is $4!$

Now,
 
Number of words beign with VA is $3!$  

Words beign with VE are:

$VEAMR$

$VEARM$

$VEMAR$

$VEMRA$

$VERAM$

$VERMA$

Therefore,

The Rank of the word VERMA

$= 4 × 4! + 3! + 6$ 

$= 96 + 6 + 6$

$=108$

Therefore,

Correct option A) 108

#Be Brainly❤️