if the letters of the word violent are arranged at random, find the probability that vowels occupy odd positions.
answer should 4/35
I can't solve this problem solve that please
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SOLUTION: In a random arrangement of letters of word VIOLENT how many ways are there that the vowels occupy odd positions only. this can only happen in one way. ... since there are 4 ways that can happen as we just calculated above, then the total ways you can get 3 vowels in only the odd position is 4 * 144 = 576.
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