Question

If the lift is moving up with a constant velocity of 2
m/s, then the tension in the string is:
(Take g = 10 m/s2)
Lift
5 kg
2 m/s ​

Answer 1

Answer:

The mass of the lift is 1000kg, the acceleration is 1m/s

2

and the acceleration due to gravity is 9.8m/s

2

.

The tension developed in string is given as,

T=mg+ma

=1000×9.8+1000×1

=10800N

Explanation:

Thus, the tension developed in the string is 10800N.

Answer 2

Answer:

HI YOUR ANSWER IS 20%

Explanation:

Suppose the mass of the man is m then its weight in rest frame will be W1 =mg

When he is in an elevator going upward direction then he will feel a downward psuedo force and thus the weight (downward)

will increase and the new weight will be

W2 = mg + Fpsuedo = mg+ma = m(g+a) = m(10+2)

= 12m

so the increment will be W2-W1/W1 x 100%

= 12m-10m/10m x 100%

= 20%