if the lift use 5 sec for 1 st floor ,how many time he want to go in 19th floor
Answers
Answered by
1
Answer:95secs
Step-by-step explanation:
1st floor=5sec
Then,
19th floor=
5 *19=95 secs
Answered by
0
Answer:
5sec=1
?=19
let second is equals to X and floor is equals to y
X is inversely proportional to y
x=ky
5=k×1
k=5/1=5
X is inversely proportional to y
x=ky
s=5×19=95second
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