if the light from the sun subtend an angle Q at the pole of a concave mirror of focal length f where will it converts also find the diameter of the image draw the necessary ray diagram
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AB= Ds is diameter of sun. The sun being at infinity , the image will be formed at focus F. The diameter of image is Di.Angle Q is small. Therefore, object distance, u= Ds/<Q.
Di/Ds= magnification = v/u=f/u=R/2u.
Therefore, Di=(R/2u)Ds=(R/2Ds/Q))Ds.= (1/2)QxR OR
Di=(1/2)Q(2f)=Qxf
Explanation:
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