Question

If the line (2 lambda-1)x + (3 lambda-4)y + 5=0 makes equal intercepts on the axes then lambda =​

Answer 1

5x+3y−2=0

(3x−y−4=0)×3

14x−10=0

x=

7

5

5×

7

5

+3y−2=0

3y+

7

−14+15

=0

3y=

7

−1

⇒y=−1/21

P(

7

5

,

21

−1

)

Similarity x−y+1=0

−

2

x−

+

y

−

+

2

=0

−x+1=0,x=1 and y=2

Q(I,2)

equation of line passing through P & Q

5x+3y02=0

3x−y−4=0)×3

14x−14=0

x=1

y=−1

P(I,−)

2X−Y−2=0

−

x

−

+

y

−

1

=0

x−3=0

x=3

y=4

Q(3,4)

Equation of line PQ

y+1=

3−1

4+1

(x−1)

y+1=

2

5

(x−1)

2y+2=5x−5

5x−2y−7=0