if the line (2k-1)X + 5y + 7k-3=1, passes through the origin, find k
PLEASE ANSWER ONLY IF YOUR ANSWER IS CORRECT OTHERWISE DONT ANSWER ITS A HUMBLE REQUEST!!!
Answers
Answered by
0
The Given Line Passes Through origin so and a line is considered to be passing from origin when its co-ordinates are (0,0)
So,
x,y = (0,0)
Substituting values of x and y in the given equation of line
(2k-1)X + 5y + 7k-3=1
(2k-1)0+ 5*0 + 7k-3=1
0 + 0 + 7k - 3 = 1
7k = 1 + 3
7k = 4
k = 4/7
So,
x,y = (0,0)
Substituting values of x and y in the given equation of line
(2k-1)X + 5y + 7k-3=1
(2k-1)0+ 5*0 + 7k-3=1
0 + 0 + 7k - 3 = 1
7k = 1 + 3
7k = 4
k = 4/7
20001mariyam:
hoping that your answer is correct
Similar questions