if the line 2x+3ay=1 and 3x+4y+1=0 are mutually perpendicular to each other the a=
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3ay=-2x+1 or,y= -(2/3a)x+1/3a
slope= -2/3a
for second line
slope= -(3/4)
now (-2/3a)(-3/4)=-1
or a=-1/2 (ans)
slope= -2/3a
for second line
slope= -(3/4)
now (-2/3a)(-3/4)=-1
or a=-1/2 (ans)
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