If the line 2x+3y-4 =0 is perpendicular to 3x-ay +5 =0, then find 'a'
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Step-by-step explanation:
if the two lines are ⊥ than the lines would intersect at only at point.
∴ the lines have a unique solution represented as a1/a2 ≠b1/b2
⇒ 2/3 ≠-3/a and hence a≠ -9/2
i.e. a can take any value other than -9/2
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