If the line 3x-2y + 6 = 0 meets X-axis and
Y-axis respectively at A and B, then the
equation of the circle with radius AB and
centre at A is
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Step-by-step explanation:
(-2,0) A. (0,3) B
radius is AB, √4+9=√13
the center is A
eqn: (x-h)²+(y-k)²=r²
(x+2)²+(y)²=13
x²+y²+4x-9=0
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