Question

If the line 3x+4y-1=0 touches the circle (x-1)^2+(y-2)^2=r^2 , then the value of r will be​

Answer 1

Answer:

find the value of K, it slope of

one of the lines represented by

40² + koy + y² =0 is four times

the slope of the other line

Answer 2

Answer:

r = 24

Given:

equation - 3x+4y-1=0

(x-1)^2+(y-2)^2=r^2

To find:

value of r

Step-by-step explanation:

We have equation of the circle is x

2+y^2=4r^2

or, x^2+y^2=( 2r)^2

x=y+2 is tangent to the circle.

Centre of the circle: (0,0)

Tangent is always perpendicular to the radius of the circle.

So,  

2r= 2∣x−y−2∣

at (x=0,y=0)

or, r= 24​

Hence, 24 is the correct answer.

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