Question

If the line (3x+4y+5)+k(x+2y-3)=0 is parallel to y-axis then the value of k is

Answer 1

Hi Mate!!!

If two lines are // their slopes are equal .

Given line can be re write as

x ( 3 + k ) + y ( 4 + 2k ) + 5 - 3k = 0

Itz Slope =. -( 3+k ) /( 4 + 2k )


Equation of line // to y axis is X = 0

And itz slope is 1


Now both given lines are // so, their slopes are equal

=>

1 = - ( 3 + k ) / (4 + 2k)

k = -7/3






Have a NYC tym....



Slope of any line in the form of this ax + by + c = 0

is -a / b

Answer 2

Answer:

k = -2.

Step-by-step explanation:

Given Equation is (3x + 4y + 5) + k(x + 2y - 3) = 0

⇒ 3x + 4y + 5 + kx + 2ky - 3k = 0

⇒ (3 + k)x + (4 + 2k)y + (5 - 3k) = 0

Given that the equation is parallel to y-axis,then coefficient of y = 0

⇒ (4 + 2k) = 0

⇒ 4 = -2k

⇒ k = -2.

Hope it helps!