Question

If the line 3x + 4y = 7 is a normal at a point
P=(x1, y1) of the hyperbola 3X^2– 4y^2 = 1,
then the distance of P from the origin
is
(A)✓319 / 12
(B)✓337 / 12
(C)✓423 / 12
(D)✓527 / 12​

Answer 1

Answer:

All wrong options.

The Correct answer is

$\frac{ \sqrt{7278 - 2940 \sqrt{6} } }{6}$

But a close approximation can be √306 / 12.