if the line 3x-7y+13=0 and kx+2y-5=0 are perpendicular to each other,find the value of k
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Answered by
4
Answer:
k=14)3
m1=-3/-7=3/7
m2=-k/2
since they are perpendicular
m1×m2=-1
3/7×-k/2=-1
3k=14
or k=14/7
hope it helped
Answered by
0
Answer:3/14
Step-by-step explanation:
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