Question

. If the line (3x – y + 5) + K(2x - 3y - 4) = 0 is parallel to y-axis, then K= ​

Answer 1

Answer:

-1/3

Step-by-step explanation:

We need to find out what the slope of (3x-y+5) + k (2x-3y-4) =0 is. We will need to make that slope undefined as vertical lines have no slope (some say infinite slope). 3x - y + 5 +2kx - 3ky - 4k = 0

y + 3ky -3x -2kx +(5 - 4k) = 0

y(3k + 1) - 3(x + [(2/3)kx)] + (5 - 4k) = 0

y(3k + 1) = 3(x +[(2/3)kx)] - (5 - 4k)

y = [3(x +(2/3)kx) - 5 + 4k]) / (3k + 1)

To make the denominator zero, thus making the line parallel to the y axis, we need 3k + 1 = 0 or k = -1/3

Hope this helps! Do mark me the brainliest!

Answer 2

Answer:

• 234xy

Step-by-step explanation:

k=234xythis is your answer