If the line giwn by 3x + 2ky = 2 and
2x+5y+1=0 are parallel then find the value
of K.
Answers
Answered by
2
Answer:
Condition for the lines to be parallel is
a
2
a
1
=
b
2
b
1
=
c
2
c
1
Here the equations are
3x+2ky=2 and 2x+5y+1=0
So, a
1
=3,b
1
=2k,c
1
=−2 and a
2
=2,b
2
=5,c
2
=1
∴
a
2
a
1
=
2
3
,
b
2
b
1
=
5
2k
and
c
2
c
1
=
1
−2
=−2
∴
5
2k
=
2
3
∴k=
4
15
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