If the line l intersects the curve y/2=x square -7 at (2,a) and (1,b) then what is the slope of line l
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Answer:
Let y=Y,x−1=X
Then, the equation becomes Y
2
=4X.
So, the focus =(2,0)
Any line through the focus is y=m(x−2)
On solving this with y
2
−4(x−10
m
2
(x−2)
2
=4(x−1)
⇒m
2
x
2
−4(m
2
+1)x+4(m
2
+1)=0
If m
=0,D=16(m
2
+1)
2
−16m
2
(m
2
+1)
=16(m
2
+1)>0, for all m
But, if m=0, then x does not have two real distinct values.
So, mϵR except m=0
∴mϵR−{0}.
Step-by-step explanation:
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