if the line represented by the equation 3x+ky=8 passes through the point (2,2) then find the value of k
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Answered by
8
Hey friend, ☺️ here is your answer ___________________________
Here 2,2 is point from where the line of equation passes. So x = 2 and y = 2
Putting these values in equation
3x + ky = 8
3*2 + k*2 = 8
6 + 2k = 8
2k = 2
k = 1
Hope this helps you..
Here 2,2 is point from where the line of equation passes. So x = 2 and y = 2
Putting these values in equation
3x + ky = 8
3*2 + k*2 = 8
6 + 2k = 8
2k = 2
k = 1
Hope this helps you..
timeismoney:
thanks
Answered by
11
Hey friend✋! here is your answer
______________________________
✔️To find - k
✅Given equation- 3x+ky=8
✔️(2,2) as we know first one denotes x coordinate & second denotes y coordinate
✅So put value of x & y in equation
✔️x=2 & y=2
✅3(2)+k(2)=8
✔️6+2k=8
✅2k=8-6
✔️2k=2
✔️k=2/2
✅k=1
So the value of k is 1
_____________________________
⭐️Hope it helps you⭐️
#Rohan ( Maths aryabhatta)♥️
______________________________
✔️To find - k
✅Given equation- 3x+ky=8
✔️(2,2) as we know first one denotes x coordinate & second denotes y coordinate
✅So put value of x & y in equation
✔️x=2 & y=2
✅3(2)+k(2)=8
✔️6+2k=8
✅2k=8-6
✔️2k=2
✔️k=2/2
✅k=1
So the value of k is 1
_____________________________
⭐️Hope it helps you⭐️
#Rohan ( Maths aryabhatta)♥️
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