Question

If the line segment joining the points A (4, 3) and B (x, 5) is a diameter of a circle with centre 0 (2, 4) then the value of x is:​

Answer 1

Answer:

Since A and B lie on the circle having centre O.

Therefore, OA = OB

(4−2)

2

+(3−3)

2

=

((x−2)

2

+(5−3)

2

2=

(x−2)

2

+4

(x−2)

2

+4=4

(x−2)

2

=0

x−2=0

x=2